Question #180799

Calculate the approximate pressure of a 2.0 mol sample of gas at 10.0 ºC and a volume of 15 L?





1
Expert's answer
2021-04-13T08:04:30-0400

10.0oC = 273 + 10 = 283 K

According to the ideal gas law,


p=nRTV=2.0mol×8.314J/mol⋅K×283K15L=310kPap=\frac{nRT}{V}=\frac{2.0mol\times8.314J/mol\cdot{K}\times283K}{15L}=310kPa


Answer: 310 kPa


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