Calculate the approximate pressure of a 2.0 mol sample of gas at 10.0 ºC and a volume of 15 L?
10.0oC = 273 + 10 = 283 K
According to the ideal gas law,
"p=\\frac{nRT}{V}=\\frac{2.0mol\\times8.314J\/mol\\cdot{K}\\times283K}{15L}=310kPa"
Answer: 310 kPa
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