Question

1. What mass of solid Lanthanum (III) oxalate nonahydrate { La2 ( C2O4 )3 ∙ 9 H2O } can be obtained from 650 mL of 0.0170 M aqueous solution of LaCl3 by adding a stoichiometric amount of sodium oxalate ?

Answer 1

Moles $=0.0170×\frac{650}{1000}=0.01105 moles$

Mass = moles × molar mass

Mass = $0.01105× 541.87=5.988 g$