Compute the corresponding (OH-) or (H3O+) in each of the following conditions. Describe the condition as acidic or base.
1. (H3O+) = 2.3 x 10-9 M
2. (OH-) = 7.4 x 10-3 M
3. (H3O+) = 8.7 x 10-4 M
1. PH = -log (H3O+) = -log 2.3 x 10-9 M = 8.64 which is basic
2. POH = -log (OH-) = -log 7.4 x 10-3 M = 2.13 which is basic
3. PH = -log (H3O+) = -log 8.7 x 10-4 M = 3.06 which is acidic
Comments
Leave a comment