Answer to Question #180308 in General Chemistry for Priya Singh

Question

For each of the following write i) a balanced chemical formula equation, ii) a complete ionic equation and iii) a net ionic equation

Aqueous chlorine is added to a solution of aluminum bromide in a single replacement reaction which forms no precipitate and bromine liquid.

i)

ii)

iii)

Answer 1

Since this reaction forms no precipitate, the new compound will not be a solid.

aqueous chlorine

+solution of aluminum bromide⟶

non−solid compound+liquid bromine

aqueous chlorine+solution of aluminum bromide⟶non−solid compound+liquid bromine

Cl₂(aq)+Al₃+Br₃^-(aq)Cl₂(aq)+AlBr₃(aq)

Cl₂(aq)+AlBr₃(aq)Cl₂(aq)+AlBr₃(aq)->non-solid compound+Br2(l)⟶non solid compound+Br2(l)⟶Al₃+Cl₂^-+Br₂(l)⟶AlCl₃+Br₂(l)

ClX₂(aq)+AlX₃+BrX₃X−(aq)⟶non-solid compound+BrX₂(l)ClX(aq)+AlBrX₃(aq)⟶non-solid compound+BrX2(l)ClX₂(aq)+AlBrX₃(aq)⟶AlX₃+ClX₃X−+BrX₂(l)ClX₂(aq)+AlBrX₃(aq)⟶AlClX₃+BrX₂(l)

Since most chloride salts are soluble (except for silver halides), AlCl₃

AlClX₃ is predicted to be aqueous.

Cl₂(aq)+AlBr₃(aq)3Cl₂ (aq)+2AlBr₃(aq)⟶AlCl₃(aq)+Br₂(l)⟶2AlCl₃(aq)+3Br₂(l)

ClX₂(aq)+AlBrX₃(aq)⟶AlClX₃(aq)+BrX₂(l)3ClX₂(aq)+2AlBrX₃(aq)⟶2AlClX₃(aq)+3BrX₂(l)

Here is the complete ionic equation:

6Cl⁻(aq)+2Al₃+(aq)+6Br^-(aq)⟶2Al₃⁺

(aq)+6Cl^-(aq)+3Br₂(l)

6Cl⁻(aq)+2AlX₃+(aq)+6BrX−(aq)⟶2AlX₃+(aq)+6ClX−(aq)+3BrX₂(l)

Cancelling out the spectator ions, we get

6Br−(aq)⟶3Br₂(l)

6BrX−(aq)⟶3BrX₂(l)

In lowest terms:

2Br−(aq)⟶Br₂(l)