Question

If you start with 365.3 g of S₈ and 571.3 g of O₂, what mass of SO₃ will be produced?

Answer 1

solution:-

given

mass of S₈= 365.3 gm

mass of O₂= 571.3 gm

moles of S₈ = $given \space mass \over molar \space molar \space mass$

= $365.3\over256$

= 1.42 moles

equation

$S_8+8O_2 \rightarrow 8SO_2$

$2SO_2+O_2 \rightarrow 2SO_3$

By stoichiometry , 1 mole of S₈ produced 8 mole of SO₂

Also , 2 mole of SO₂ produces 2 mole of SO₃

Therefore 8 mole of SO₂ produce mole of SO₃

I.e 1 mole of S₈ produce 8 mole SO₃

$\implies$

1.42 mole S₈ produce 8$\times 1.42$ mole SO₃

Answer = 11.36 mole SO₃

i.e

$\boxed{mass \space of \space SO_3 \space produced \space 908.8 \space grams}$