Answer to Question #180195 in General Chemistry for hayley samantha farah

Question

Use the following balanced reaction:

Na2 ​CO3​ + Ca(HC2​H3​O2​)2​  2NaHC2​H3​O2​ + CaCO3

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 If you have 2.61 moles of Na₂CO₃ and 3.52 moles of Ca(HC₂H₃O₂)₂, how many moles of NaHC₂H₃O₂ will be produced?

     mol NaHC₂H₃O₂   

Answer 1

The balanced equation is;

Na₂ ​CO₃​ + Ca(HC₂​H₃​O₂​)₂​ $\to$  2NaHC₂​H₃​O₂​ + CaCO₃

If we have 2.61mol of Na₂CO3 and 3.52 mol of Ca(HC₂H₃O₂)₂;

And the mole ratios Na₂CO3:Ca(HC₂H₃O₂)₂from the balanced equation is 1:1;

Then it follows that Na₂CO₃ is the limiting reagent (which will determine the amounts of products formed).

Now, mole ratios of Na₂ ​CO₃: NaHC₂​H₃​O₂ = 1:2

Thus,

moles of NaHC₂​H₃​O₂ produced $=\dfrac{2}{1}$ x Na₂ ​CO₃

$= \dfrac{2}{1}$ x 2.61 mol

$=$ 5.22 mol