Answer to Question #180191 in General Chemistry for hayley samantha farah

Question

If you have 750.0 g of HNO₃ and excess Na₂CO₃, how many grams of carbon dioxide will be produced?

Answer 1

First we need the balanced equation for the reaction;

2HNO₃ + Na₂CO₃ $\to$ 2NaNO₃ + H₂O + CO₃

Moles of HNO₃ used $=\dfrac{Mass}{MM} = \dfrac{750.0g}{63.01g/mol} = 11.9029mol$

Since Na₂CO₃ is in excess, HNO₃ is the limiting reagent

Thus moles of CO₂ will be determined by moles of HNO₃

Mole ratios of HNO₃ : CO₂ is 2:1

Moles of CO₂ $=$ $\dfrac{1}{2}x11.9029$

= 5.9514 mol

Mass of CO2 = Moles x MM

= 5.9514 mol x 44.01 g/mol

= 261.9227g