Balance this equation, and then answer the question:
CH3 OH + O2 CO2 + H2O
If you combust 56.62 g of CH3OH, how many grams of H2O will be formed?
2CH3OH+3O2→2 CO2+4H2O
2 moles of CH3OH = 4 moles of H2O
Molar Mass of CH3OH = 32.04
= 56.62/32.04 = 1.7672 moles
= 1.7672 × 2 = 3.5344 moles of H2O
Molar Mass of H2O = 18.01
= 3.5344 × 18.01 = 63.654544 g of H2O
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