Answer to Question #180180 in General Chemistry for kiera

Question #180180

Lead is a highly poisonous metal. The mass percentage of lead in the 250 g

 aqueous solution was found to be 1.2×10

−6%

 by extracting the lead with an excess of iodide and weighing the resulting 

. How many micrograms (μg) of lead iodide were measured?


1
Expert's answer
2021-04-11T23:50:49-0400

Mass percentage of Pb=1.2×106Pb=1.2×10^{-6} %

100 g of solution contains 1.2×10-6 g of Pb

250 g of solution contains 1.2×10-6 ×250/100 g of Pb=3×106gPb = 3×10^{-6}g

noofmolesofPb=3×106/207.2=1.45×108no of moles of Pb = 3×10^{-6}/207.2=1.45×10^{-8}

No of moles of PbI2=1.45×108PbI_2=1.45×10^{-8}

Mass of PbI2=1.45×108×461.01=667.48×108gPbI_2=1.45×10^{-8}×461.01=667.48×10^{-8}g

=6.674×106g=6.67μg=6.674×10^{-6}g=6.67\mu g of lead iodide


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