A student is given 2 solutions: 15.0 ml of a 0.125 M KOH solution and 12.0 ml of a 0.175 M H2SO4 solution. Calculate the following:
a) The amount of potassium sulfate produced.
b) What is the limiting reactant? What is the excess reactant?
c) How many grams of the excess reactants are in excess?
2KOH + H2SO4 → K2SO4 + 2H2O
Moles of KOH =
Amount of
Limiting reactant is
Excess reactant is
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