How many liters of solution are needed to make a 1.66 M solution containing 333.44 grams of KMnO4?
C=n/V
V=n/C
n=m/M
M=39+55+4*16=158(g/mol)
n=333.44/158=2.11(mol)
V=2.11/1.66=1.27(L)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment