Question

2Al+3Cl subscript 2 yeilds NaCl. What mass of Cl subscript 2 is needed to completely react with 1.5 grams of Na

Answer 1

Moles of Na $= \frac{1.5}{22}=0.068 moles$

Moles of Cl$=\frac{0.068×3}{2}=0.102moles$

Mass of Cl $=$ $0.102×35=3.57g$