Question

How many grams of sodium nitrate will be produced if you start with 135.0 grams of sodium hydroxide?

Answer 1

HNO₃ +NaOH->NaNO₃ + H₂O

1 mole of NaOH = 1 mole of NaNO₃

molar mass of NaOH = 39.997 g/mol

Molar Mass of NaNO_{3 =} 84.9947 g/mol

135 g of NaOH = 135/39.997

= 3.375 moles

= 3.375 × 84.9947 = 286.8786g of NaNO₃