What volume of NH3 gas in liters is produced at STP when 0.61 L of a 1.81 M NH4Cl solution reacts according to the above equation?
NH4Cl = NH3 + HCl
Mole = volume × concentration
= 0.61L × 1.81M = 1.1041mole
1 mole NH4Cl = 22.4 L NH3
1.1041 mole NH4Cl =1.1041 × 22.4L NH3
= 24.73L NH3
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