A gas sample occupies a volume of 12.0 L at 50oC and 700 Torr. How many moles of gas are contained in the sample?
V = 12 L
T = 50⁰C = 273 + 50 = 323 K
P = 700 torr
R = 62.363577 L.Torr / K.mol
PV = n RT
700×12 = n ×62.363577 × 323
n = 2.39 mol
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