When 1956 J of heat energy is added to 44.1 g of hexane, C6H14, the temperature increases by 19.6*C.
calculate the molar heat capacity of C6H14
Molar mass of C6H14C_6H_{14}C6H14 is 86.176gmol−186.176gmol^{-1}86.176gmol−1
number of moles, n=massmolar mass=44.1g86.176gmol−1=0.512moln=\frac{mass}{molar \space mass}=\frac{44.1g}{86.176gmol^{-1}}=0.512moln=molar massmass=86.176gmol−144.1g=0.512mol
molar heat capacity of C6H14,C=qnΔT=1956(0.512)(19.6)=194.91Jmol−1oC−1C_6H_{14}, C=\frac{q}{n\Delta T}=\frac{1956}{(0.512)(19.6)}=194.91Jmol^{-1o}C^{-1}C6H14,C=nΔTq=(0.512)(19.6)1956=194.91Jmol−1oC−1
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments