Answer to Question #179076 in General Chemistry for edizon

General Chemistry

Question #179076

Solid potassium chlorate, KClO3, decomposes to form solid potassium chloride and diatomic oxygen gas.

Expert's answer

2KClO₃ $\to$ 2KCl + 3O₂

6O^-2 - 12 e^-= 6O⁰ $\mid$ *1

Cl⁺⁵ + 6 e^-= Cl^-1 $\mid$ *2

6O^-2+ 2Cl⁺⁵ = 6O⁰ + 2Cl^-1

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