Question

What mass (in grams) of CuCl₂ would be needed to make 675 mL of 1.76 M solution?

Answer 1

$\bigstar$

$\boxed{ Molarity ={ n_{solute}\over V_{solution}} }$

$\implies$$\boxed{Molarity = }$ $\boxed{m(given\space mass)\over {(molar \space mass)\times V_{litre}}}$

$\bigstar$

$\boxed{Molarity = }$ $\boxed{m\over {134.45 \times 0.675}}$

$\bigstar$

$\boxed{mass = 159.72\space grams}$