Answer to Question #178670 in General Chemistry for John taylor

Question #178670

A sample of air at 60.0 kPa has a volume of 397 mL. If the temperature is kept constant while the volume is changed to 565 mL, what is the resulting pressure of the gas?

Expert's answer

$P_2=\frac {60kPa×397mL}{565mL}$

$P_2=42.16kPa$

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