Question

A sample of helium has a volume of 34.8 L at a temperature of 25.0˚C. What would the volume be if the temperature was increased to 60.0˚C at a constant pressure?

Answer 1

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

New volume is $V_2$

$V_2= \frac{V_1×T_2}{T_1}$

$V_2=\frac{34.8×[273+60]}{[273+25]}=38.89L$