Answer to Question #178578 in General Chemistry for jenne

Question

an electron (m_e = 9.10939 × 10^–28 g) moving at 4.00 × 10⁶ m/s in an electron microscope

Answer 1

$λ = \frac{h}{p} = \frac{h }{ m × v}$

$\lambda=\frac{6.62 × 10 ^{-34} }{ [(9.10939 ×10^{-28 })×(4.0×10^6)]}$

$\lambda= 1.816806614×10^{-13} m$

$\lambda=0.0001816806614 nm$