Given:
H2 (g) + I2 (g) ⇌2HI (g)
At 400. K for the reaction above, Kp = 62.5.
In another experiment at a different temperature, H2 (g), I2 (g), and HI (g) are introduced to a flask at pressures of 0.040 atm, 0.020 atm, and 0.090 atm, respectively. If the partial pressure of HI (g) decreases by 50%, calculate the pressure of each species when equilibrium is established.
Pressure=(0.040+0.020+0.090)×50/100 = 0.075 atm
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