When copper is mixed with silver nitrate, the products of the reaction are copper(II) nitrate and solid silver.
If you start with a copper penny with a mass of 3.05 g and 208 mL of 0.100 M silver nitrate, determine the limiting reagent
The balanced equation is:
Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag
To determine the limiting reactant, there should be an amount of each reactant calculated (in moles):
"n(Cu)=\\frac{3.05g}{63.55g\/mol}=0.0480mol"
"n(AgNO_3)=0.208L\\times0.100M=0.0208 mol"
According to the equation, the Cu : AgNO3 molar ratio is 1 : 2.
The actual ratio is 0.0480 : 0.0208, which is 2.3 : 1, hence Cu is in excess, and AgNO3 is limiting.
Answer: AgNO3
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