Answer to Question #177762 in General Chemistry for Maggie wong

Question #177762

When copper is mixed with silver nitrate, the products of the reaction are copper(II) nitrate and solid silver.

If you start with a copper penny with a mass of 3.05 g and 208 mL of 0.100 M silver nitrate, determine the limiting reagent


1
Expert's answer
2021-04-05T07:50:02-0400

The balanced equation is:

Cu + 2AgNO3 --> Cu(NO3)2 + 2Ag

To determine the limiting reactant, there should be an amount of each reactant calculated (in moles):

"n(Cu)=\\frac{3.05g}{63.55g\/mol}=0.0480mol"

"n(AgNO_3)=0.208L\\times0.100M=0.0208 mol"


According to the equation, the Cu : AgNO3 molar ratio is 1 : 2.

The actual ratio is 0.0480 : 0.0208, which is 2.3 : 1, hence Cu is in excess, and AgNO3 is limiting.


Answer: AgNO3

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