Question

Determine the value of the equilibrium constant, Q for the chemical reaction given below, if 0.230 moles of Mg, 0.087, sulfate (SO4) 0.860, CO2 with 0.0580 and 0.120 moles of water vapor are there in a 5 liters container and at an equilibrium.

Mg= 0.230

SO4= 0.860

CO2= 0.0580

water vapor or H2O= 0.120

container 5 liters

                              

substitute the value of the compounds

Answer 1

$MgCO_3 + H_2SO_4 = MgSO_4 + CO_2 + H_2O$

Molar Conc. of Mg = 0.087/5

Molar Conc. of MgCO₃ =

Molar Conc. of SO₄ = 0.230/5

Molar Conc. of H₂SO₄ = 0.230/5

Molar Conc. of CO₂ = 0.0580/5

Molar Conc. of H₂O= 0.230/5

$Q = \dfrac{0.875/5×0.230/5}{0.0580/5×0.230/5}= 15.1$