Question

What is the molarity of 49 g of H₂SO₄ dissolved in 0.3 L of solution?

Answer 1

Solution.

$m=49g;$

$M(H_2SO_4)=98g/mol;$

$V=0.3L;$

$M=\dfrac{n}{V};$

$n=\dfrac{m}{M(H_2SO_4)};$

$n=\dfrac{49g}{98g/mol}=0.5mol;$

$M=\dfrac{0.5mol}{0.3L}=1.67M;$

Answer: $M=1.67M;$