A 4.6 g sample of XO2 occupies 2.24 L at STP. Find X.
At STP, 1 mole of any gas occupies a volume of 22.4 L.
4.6 g of a gas at STP occupies a volume of 2.24L.
Hence, the number of moles of gas "=\\frac{2.24}{22.4} \u200b=0.1 moles."
0.1 moles of a gas = 4.6 g.
1 mole of a gas "=4.6\u00d7\\frac{1}{0.1}=46g"
Thus, the molecular weight of gas is 46g/mol.
It is the molecular weight of NO2 gas.
Hence = X is N (nitrogen)
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