What is the empirical formula of the compound containing 2.80 g Fe, 1.35 g Al and 2.40 g O?(Fe:56, Al:27, O:16)
Solution:What is the empirical formula of the compound containing 2.80 g Fe, 1.35 g Al and 2.40 g O?(Fe:56, Al:27, O:16)
Answer- The corresponding numbers of atoms in moles are
2,80gFe*(1molFe/56)=0.05 mol Fe
1,35gAl*(1molAl/27)=0.05 mol Al
2,40gO*(1molO/16)=0.15 mol O
Thus,we can accurately represent this compound with formula of Fe0,05 Al0,05 O0,15
Of course,per accepted conventionformula contain whole-number subscripts,which can be achieved by dividings euch subscript by the smaller subscript Fe0,05/0,05 Al 0,05/0,05 O 0,15\0,05 or
FeAlO3
Comments
Leave a comment