Calculate the molar mass of the following compounds. Fe2O3 and H2SO4 (Al:27, Fe:56, S:32, O:16, H:1)
Fe2O3=(56×2)+(16×3)Fe_2O_3=(56\times2)+(16\times3)Fe2O3=(56×2)+(16×3)
=112+48=160=112+48=160=112+48=160
H2SO4=(1×2)+(32)+(16×4)H_2SO_4=(1\times2)+(32)+(16\times4)H2SO4=(1×2)+(32)+(16×4)
=2+32+64=98=2+32+64=98=2+32+64=98
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