How many moles of barium hydroxide, Ba(OH)2, are present in 200.5 g?
mol Ba(OH)2
How many moles of barium ions are present in Part 1?
mol Ba2+
How many moles of hydroxide ions are present in Part 1?
mol OH1-
Part I
Molar mass Ba(OH)2 = (137.327+2(16)+2(1.008))g
Ba(OH)2 = 171.34g
Therefore : 1 Mol = 171.343g
? = 235.5g
= (235.5/171.343) = 1.4Moles
PART II
1 mol of Ba+ = 137.327
? = 171.343
=1.2moles
PART III
1.4 moles = 2mol
? = 1 mol
(1.4/2) =0.7 moles
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