Try computing this problem. Find the value of equilibrium (K) in this problem. .
The reaction of CO2 with water to form carbonic acid (H2CO3) is written as follows:
CO2(g) + H2O = H2CO3(aq)
ΔGf° -394.37 -237.18 -623.2 in kJ mol-1
and
ΔGr° = -623.2 - (-394.37) - (-237.18) = +8.35 kJ mol-1
CO2(g) + H2O = H2CO3(aq)
= 8.35 kj
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