X(g) + 2 Q(g) ⇄ R(g) + Z(g) Kc = 1.3 × 10-5 at 50°C
A 1.0 mol sample of X(g) and a 1.0 mol sample of Q(g) are introduced into an evacuated, rigid 10.0 L container and allowed to reach equilibrium at 50°C according to the equation above. At equilibrium, which of the following is true about the concentrations of the gases? EXPLAIN
2 S(s) + 2 O2(g) ⇄ 2 SO2(g) K1 = 2 x 10105
2 SO2(g) + O2(g) ⇄ 2 SO3(g) K2 = 7 x 10-24
Given the value of the equilibrium constants K1 and K2 for the reactions represented above, what is the value of the equilibrium constant, K3, for the following reaction? EXPLAIN
2 S(s) + 3 O2(g) ⇄ 2 SO3(g) K3 = ?
I) At equilibrium,
[R]<[X]
This is true because the equilibrium constant Kc which is 1.3x10-5 is low. This means that at equilibrium, the concentration of products are relatively small compared to the concentration of reactants or more appropriately, the equilibrium position lies towards the left side of the reaction.
II) since the two equations are added up, the corresponding equilibrium constants will be multiplied.
K3=K1K2
K3= 2x10105x7x10-24
K3= 14x10105-24
K3= 14x1081
K3= 1.4x1082
So we can see from the answer that the closest option is
1x1082
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