Question

If it takes 0.5 L of oxygen gas kept in a cylinder under pressure to fill an evacuated 4.50 L vessel in which the pressure is 0.98 atm, what was the initial pressure of the gas in the cylinder? 

Answer 1

Volume of oxygen $V_1=0.5L$

Let initial pressure be $P_1$

and Volume of Vessel $v_2=4.5L$

pressure of vessel $P_2=0.98 atm$

Using Boyle's law we have,

$P_1V_1=P_2V_2$

$P_1\times 0.5=0.98\times 4.5\\\Rightarrow P_1=8.82atm$