Question

A gas at 314 K occupies a volume of 0.67 L.  At what Kelvin temperature will the volume increase to 1.05 L?

Answer 1

$T_2=\frac {T_1×V_2}{V_1}$

$T_2=\frac {314K×1.05L}{0.67L}$

$T_2=492K$