Question

A sample of neon gas occupies 0.228 L at 0.860 atm.  What will be its volume at 0.0284 atm of pressure?  

Answer 1

$V_2=\frac {P_1V_1} {P_2}$

$V_2=\frac {0.228×0.860}{0.0284}$

$V_2=6.9L$