Calculate the [H3O+] and the [OH-] for each of the following:
0.0454 M H3PO4
1.00 x 10-8 M KOH
7.78 x 10-3 M H2SO4
0.0213 M Al(OH)3
[H3+O]=3.80×10−11M[H_3^{+}O] =3.80×10^{-11}M[H3+O]=3.80×10−11M
[OH−]=2.9×10−11M[OH^{-}] =2.9×10^{-11}M[OH−]=2.9×10−11M
[H3+O]=0.048M[H^{+} _3O]=0.048M[H3+O]=0.048M
[OH−]=0.037M[OH^{-}] =0.037M[OH−]=0.037M
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