What volume does 6.76 × 1021 molecules of N2 occupy at STP?
1 mole of N2 = 6.022 × 10^ 23
= 6.76 × 10 ^21/ 6.022 × 10^ 23
= 0.01moles of N2
1 mole of any gas ocuppy 22.4 L
= 22.4 × 0.1
= 2.24L
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