Answer to Question #176422 in General Chemistry for anonymous

Question

Oxidation and Reduction.

 

What is the oxidation number of each of the elements in the following compounds?

CaCl₂

PbO₂

NaH

Na₃PO₄

O₂

Answer 1

The Oxidation number of each element in each compound is given below

1. In CaCl2

Ca= +2

Cl= -1

2. In PbO2

Pb= +4, O= -2

3. In NaH

Na=+1, H=-1

4. In Na3PO4

Na= +1, P= +5, O=-2

5. In O2

O=0