Question

Acetylene a gas used in welding is periodic Ed be the following reaction of calcium carbide CaC2 with water. How much calcium carbide is needed to produce 75.00g of acetylene

Answer 1

$$CaC_2 + 2H_2O = Ca(OH)_2 + C_2H_2$$

$$n(C_2H_2) = m/M = 75.0g/26(g/mol) = 2.885 mol$$

$$n(C_2H_2) = n(CaC_2) = 2.885 mol$$

$$m(CaC_2) = nM = 2.885mol*64g/mol = 184.64 g$$