Answer to Question #175433 in General Chemistry for Ralphe

Question

How many grams water is needed to prepare 2.8% by mass of 367g of sugar solution?

Answer 1

Sugar = Sucrose = C12H2O11

Molar Mass of C12H2O11 = 342

Mass percentage = Mass of solute /Mass of solution

Mass of sln 367

Mass % = 2.8%

Let Mass of solute be X

2.8 = X/367

X = 10.276 g

Mass of solvent = Mass of Solution - Mass of Solute

Mass of Solvent = 367- 10.276

356.724

= 356.724 g