(a) A 25.0 cm3 sample of 0.25 mol dm-3 nitric acid solution is titrated with 0.10 mol dm-3 sodium hydroxide. Calculate the pH of the solution -
(i) Before any sodium hydroxide has been added
(ii) After the addition of 10.0 cm3 sodium hydroxide
(iii) After the addition of 25.0 cm3 sodium hydroxide
(iv) After the addition of 50.0 cm3 sodium hydroxide
(v) After the addition of 62.5 cm3 sodium hydroxide
(vi) After the addition of 75.0 cm3 sodium hydroxide
(vii) After the addition of 100.0 cm3 sodium hydroxide
Cocentration of the acid = 0.25M
PH before NaOH added = -log 0.25 = 0.6
Comments
Leave a comment