Question

How many moles of N₂ (g) are present in 1.00 L of N₂ (g) at 100. °C and 1 atm? ______ moles

Answer 1

$PV=nRT$

$n=$ $PV\over RT$

$(1atm)(1L) mol K\over (100+273k)(62.4K.torr)$

$=4.296\times 10^{-5}mol$