Answer to Question #174654 in General Chemistry for Jasmine

Question

The rate law for the reaction of NO with Cl2 was found to be

2 NO(g)+ Cl2(g) -> 2 NOCl(g) Rate= k[NO]² [Cl2]

a. What is the order of the reaction with respect to NO? With respect to Cl2?

b. Suppose that you triple the concentration of NO and simultaneously decrease the concentration of Cl2 by a factor of 8. Will the reaction be faster or slower under the new conditions? How much faster or slower? (Assume that the temperature is the same in both sets of conditions.)

Answer 1

a) Order with respect to $NO$ is 2 and order with respect to $Cl_2$ is 1.

b) The reaction will be faster by $0.256mol/litre /sec$