Calculate molar concentration of a sodium hydroxide solution,if 25cm³ of it requires 20.5cm³ of 0.103 mol/dm³ solution of tetraoxosulphate(VI) acid for neutralization.what is the concentration of the alkaline solution in g/dm³
Molar Mass of sodium hydroxide= 39.997 g/mol
25cm3 = 25 g
= 25/39.996 = 0.625048 mol
Molar Mass of tetraoxosulphate (VI) H2SO4 = (2+32+64) = 98g/mol
0.103 × 98 = 10.094g
20.5g of 10.0094 dm3= 20.5/10.904 = 1.880044
= 0.625048/ (0.025 + 1.880044)
= 0.328101mol/L
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