A solution A was prepared by dissolving 60 g of NaOH in 100ml of distilled water. Later, 10 ml where taken and poured into a 250 ml volumetric flask. A solution B is obtained
a-calculate mass concentration of solution A
b- Deduce molar concentration of A
c- Find molar concentrantion of B Given : M NaOH= 40g/mol
a. mass concentration of solution A = 60g*100%/160g = 37.5%
b. n(NaOH) = 60g/40g/mol = 1.5 mol
molar concentration of A = 1.5mol/0.16L = 9.375 M
c. n(NaOH) = 9.375M*0.01L = 0.09375 mol
molar concentrantion of B = 0.09375 mol/0.25L = 0.375 M
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