Question #174360

A balloon containing 117 L of gas at 1 atm would have what volume at a pressure of 3 atm? (Assume temperature and number of particles stays constant.)


1
Expert's answer
2021-03-23T04:21:35-0400

P1V1=P2V2P_1V_1=P_2V_2


117L×1atm=V2×3atm117L×1atm=V_2×3atm


V2=117×1atm3atmV_2=\frac {117×1atm}{3atm}


V2=39LV_2=39L


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