A 12.7 L sample of gas is under a pressure of 69.8 mm of Hg. What will be the pressure of the gas, in atm, when the volume increases to 20.1 L (assume that the temperature is held constant)?
P1V1 = P2V2
= 69.8×12.7 = 20.1×X
20.1X = 886.46
X = 886.46/ 20.1
= 44.10mm of Hg
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In a percentage composition investigation a compound was determined to be composed of calcium, carbon, and oxygen. During the investigation the following data was obtained. Total mass of sample37.28 gMass of calcium14.91 gMass of carbon4.47 gDetermine the percentage composition of the compound.
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