Question #172764

In an experiment, the initial concentration of NO2 was 0.00650 mol/L. What is the half-life?


1
Expert's answer
2021-03-18T03:01:54-0400

half life t1/2 = [Ao]2k\frac{[A_o]}{2k}

[Ao] = initial concentration = 0.00650 mol/L

t1/2 = 0.006502k\frac{0.00650}{2k}


t1/2 = 0.00325k\frac{0.00325}{k}


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