In an experiment, the initial concentration of NO2 was 0.00650 mol/L. What is the half-life?
half life t1/2 = [Ao]2k\frac{[A_o]}{2k}2k[Ao]
[Ao] = initial concentration = 0.00650 mol/L
t1/2 = 0.006502k\frac{0.00650}{2k}2k0.00650
t1/2 = 0.00325k\frac{0.00325}{k}k0.00325
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments