What concentration of NaC2H3O2 must be added to 0.1 F HC3H3O2 to give a hydronium concentration of 2 x 10 to the negative 6 gfw per liter?
Molar Mass of NaC2H3O2 = 82.0343 g/mol
Molar Mass of HC3H3O2 = 72.067
= HC3H3O2 0.1 F = Number of mfw/V
= 0.1× 72.067ml = 7.2067 mfw
Formalities of NaC2H3O2 = 0.1
0.1× 82.0343 = 8.2 mfw
Hydronium concentration = 1 ×10 ^ -7
2×10^-6/1×10^-7 = 2×10^1 = 20
8.2x/7.2 = 20
=18
= 18 g/L
Comments
Leave a comment