Whats 3co2+H1
Subtract the sum of the heats of formation of the reactants from that of the products to determine ΔH\Delta HΔH :
Δ=–110.53kJ/mol–(–285.83kJ/mol)=175.3kJ.\Delta = –110.53 kJ/mol – (–285.83 kJ/mol) = 175.3 kJ.Δ=–110.53kJ/mol–(–285.83kJ/mol)=175.3kJ.
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