Answer to Question #172389 in General Chemistry for Julia

Question

Lead (II) iodide, PbI2 has a Ksp = 7.1 x 10-9. Calculate the solubility (in g/L) of PbI2 in 0.40 M Pb(NO3)2 solution. [bonus 2] How many times is PbI2 more or less soluble in 0.40 M Pb(NO3)2 solution than in pure water?

Answer 1

Solubility =$4.213×10^{-4}M$

It would be twice more soluble than in pure water.